GAMSAT chemistry: what to study for Section 3

General and physical chemistry make up a large share of Section III. Here are the topics that come up most, how to study them and two practice questions to try.

Start practising freeNo credit card required.

Chemistry topics to know

  • Moles and stoichiometry: molar mass, concentration, dilution and limiting reagents.
  • Equilibrium: equilibrium constants and Le Chatelier’s principle.
  • Acids and bases: pH, pKa, buffers and titration curves.
  • Thermodynamics and kinetics: enthalpy, entropy, Gibbs free energy, rates and activation energy.
  • Redox and electrochemistry: oxidation states, half-equations and galvanic cells.
  • Gases and solutions: the ideal gas law, partial pressures and solubility.

Organic chemistry has its own guide.

How to study GAMSAT chemistry

  • Get moles fluent first. Almost every calculation depends on them.
  • Practise logs without a calculator so pH and pKa questions take seconds.
  • Explain equilibrium shifts in words before reaching for an equation.
  • Practise from data. Titration curves, rate tables and energy diagrams are common stimuli.

GAMSAT chemistry practice questions

Choose your answer, then open the explanation.

Section III Equilibrium

Ammonia is made by the reaction N₂(g) + 3H₂(g) ⇌ 2NH₃(g). The forward reaction is exothermic.

Which change would increase the equilibrium yield of ammonia?

  1. A Raising the temperature
  2. B Lowering the pressure
  3. C Removing ammonia as it forms
  4. D Adding a catalyst
Show the answer and explanation

C. Removing a product shifts the equilibrium to the right to replace it. Raising the temperature favours the endothermic reverse reaction (A). Lowering the pressure favours the side with more gas molecules, which is the left with 4 against 2 (B). A catalyst speeds up both directions equally, so it changes how fast equilibrium is reached but not where it lies (D).

Section III Moles

What mass of sodium hydroxide (molar mass 40 g/mol) is needed to make 250 mL of a 0.2 mol/L solution?

  1. A 0.5 g
  2. B 2 g
  3. C 5 g
  4. D 8 g
Show the answer and explanation

B. Moles = concentration × volume = 0.2 × 0.25 = 0.05 mol. Mass = moles × molar mass = 0.05 × 40 = 2 g. Answer D is the mass for a full litre: it leaves out the 250 mL.

More practice: free GAMSAT practice questions and Section 3 tips.

Common questions

How much chemistry is in the GAMSAT?

Chemistry is roughly 40% of Section III, split between general and physical chemistry and organic chemistry. Because Section III counts twice in the overall score, chemistry is one of the most valuable subjects to study.

What level of chemistry does the GAMSAT assume?

About first-year university. Questions usually give you a passage or data and ask you to reason from it, so understanding concepts matters more than memorising facts.

Today’s unit is ready.

Create a free account and start it now. No credit card required.

Start practising free